Question

log base2 into log base3 log base x 81 =1

Answer 1

Step-by-step explanation:

$log_2\times log_3\times log_x 81=1 \\ \implies \: log_2\times log_3 81= {x}^{1} \\ \implies \: log_2\times log_3 {3}^{4} = x \\ \implies \: log_2\times 4log_3 {3} = x \\ \implies \: log_2\times 4 \times 1 = x \\ \implies \: log_2\times 4 = x\\ \implies \: log_2 {2}^{2} = x\\ \implies \: 2log_2 {2} = x\\ \implies \: 2 \times 1= x \\ \implies \: 2 = x \\ \implies \: \huge \fbox{ x = 2}$

Answer 2

Answer:

2

Step-by-step explanation:

log base 2 × log base 3 81= x^1

log base 2 × log base 3 3^4 = x

log base 2 × 4 log base 3 3 = x

log base 2 × 4 ×1 = x

log base 2 2^2 = x

2 log 2 = x

2 × 1 = x

X = 2