Question

the application of manure increase the output of a crops by 10% in the first year, 5% in the second year and 4% in the third year . if the production of crop in the year 2012 was 3.5 tons per hectare find the production of crops per hectare in 2008

Answer 1

Question :- The application of manure increase the output of a crops by 10% in the first year, 5% in the second year and 4% in the third year . if the production of crop in the start of year 2012 was 3.5 tons per hectare find the production of crops per hectare at the end of 2008 ?

Solution :-

Let us assume that, the production of crops per hectare at the end of 2008 was x .

Than,

→ in first year crops increase by = 10% .

So,

→ in the end of 2009 crop per hectare was = x + 10% of x = (100 + 10)% of x = 110% of x = (11x/10)

Now,

→ in second crops increase by = 5% .

So,

→ in the end of 2010 crop per hectare was = (11x/10) + 5% of (11x/10) = (100 + 5)% of (11x/10) = 105% of x = {(11x/10) * (105/100)} = (11x/10) * (21/20) = (231x/200).

Now,

→ in third year crops increase by = 4% .

So,

→ in the end of 2011 crop per hectare was = (231x/200) + 4% of (231x/200) = (100 + 4)% of (231x/200) = 104% of (231x/200) = (231x/200) * (104/100) = (231x/200) * (57/50) = (231x * 57) / (200 * 50) = (13,167x/10,000)

Also, we have given that, the production of crop in the start of year 2012 was 3.5 tons per hectare .

Therefore,

→ Production at the end of 2011 = Production at the start of 2012

→ (13,167x/10,000) = 3.5 tons.

→ 13167x = 3.5 * 10000

→ 13167x = 35000

→ x = 2.65 tons / hectare. (Ans.)

Hence, the production of crops per hectare at the end of 2008 was 2.65 tons .

Answer 2

Step-by-step explanation:

answer is4.2 .....................