Question

log18withbase12=a and log54with base 24=b
finda×b+5(A-B)=

Answer 1

By change base rule
$a=log_{12} 18= \frac{log_{10} 18}{log_{10} 12}$
$b=log_{24} 54= \frac{log_{10} 54}{log_{10} 24}$
by using log to the base 10 table
a=1.1632
b=1.2552
ab+5(a-b)=1.46+5(-0.092)=1.46-0.46=1

Answer 2

Here, it's easy bro,                                                                                                      By change base rule


by using log to the base 10 table
a=1.1632
b=1.2552
ab+5(a-b)=1.46+5(-0.092)=1.46-0.46=1