Question

log3 base 30 = a, log 5 base 30, then find log 8 base 30.

Answer 1

log 3 bse 30=a
log 5bse30=b
ab=[log3base30][log5bse30]
    =log[3+5]base 30
    =log 8 bse30

thus log8bse 30=ab