Question

Log32 + log 125 + log7 - log28

Pls do with steps

Answer 1

We know, log m + log n = log mn
log m - log n = log (m÷n)

××××××××××


log 32 + log 125 + log 7 - log 28

=> log (32×125×7÷28)

=> log (8×125)

=> log 1000

=> log 10³

=> 3 log 10

=> 3 × 1

=> 3



I hope this will help you

(-:

Answer 2

Hi Friend !!!

Here is ur answer !!!

log 32 + log125 + log 7 - log 28

= log(32×125×7÷28)

= log 1000

= log 10³

= 3 log10

= 3(1)

= 3

Hope it helps u : )