Question

log729 base 243 is
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Answer 1

Answer:

Convert to exponential form log base 243 of 729=6/5.

Answer 2

Answer:

$log_{243}(729) = \frac{ log(729) }{ log(243) } \\ = \frac{ log( {3}^{6} ) }{ log( {3}^{5} ) } \\ = \frac{6 log(3) }{5 log(3) } \\ = \frac{6}{5}$