Math, asked by chindarkarjay7400, 11 months ago

M can complete a piece of work in 10 days. N is 33.33% less efficient than M. calculate the number of days required to both to complete the work?
A) 6 days
B) 8 days
C) 11 days
D) 13 days

Answers

Answered by Anonymous
16


M can complete a piece of work in 10 days. N is 33.33% less efficient than M. calculate the number of days required to both to complete the work?

A) 6 daysB) 8 daysC) 11 daysD) 13 days

Answer:   A) 6 days 

Explanation:

M = 10 days

The ratio of efficiency of M & N are 3 : 2

Hence, the time rquired for N alone = 15 days

=> Required time taken t=by both to complete the work = M x N / M + N 

= 10 x 15/ 10 + 15

= 150/25

= 6 days.

Answered by lucky1742
0
A is Right answer. .....
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