Question

M. In two moles of acetaldehyde
(CHCHO) calculate the following
a. Number of moles of carbon
b. Number of moles of hydrogen
c. Number of moles of oxygen
d. Number of molecules of acetaldehyde
(Ans.: A. 4 mol, B. 8 mol, C. 2 mol,
D. 12.044 x 1023 molecules )​

Answer 1

Answer:

molecular mass of C2H4O= 12*2+1*4+16=44g

amount of acetaldehyde= 44*2= 88g

no. of molecules of acetaldehyde= no of moles * avogadro no

=2* 6.022*10^23

=12.044*10^23 molecules