Math, asked by akash2857shelke, 4 months ago

m²-14m + 13=0 find the value of b²-4ac​

Answers

Answered by bagkakali
3

Answer:

m^2-14m+13=0

ax^2+bx+c=0

similar this equation here b= -14,a=1,c=13

b^2-4ac

=(-14)^2-4*1*13

=196-52

=144

Answered by aakankshachoud
1

m²-14m + 13=0

a=1,b=13,c=14

d=b^2-4ac

D=(-14)^2-4(1)(13)

D=196-52

D=144

So,

Your answer is 144

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