m²-14m + 13=0 find the value of b²-4ac
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Answered by
3
Answer:
m^2-14m+13=0
ax^2+bx+c=0
similar this equation here b= -14,a=1,c=13
b^2-4ac
=(-14)^2-4*1*13
=196-52
=144
Answered by
1
m²-14m + 13=0
a=1,b=13,c=14
d=b^2-4ac
D=(-14)^2-4(1)(13)
D=196-52
D=144
So,
Your answer is 144
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