Question

मान लीजिए कि f, g : $R \rightarrow R$ क्रमश: $f(x) = x + 1$, $g(x) = 2x - 3$ द्वारा परिभाषित है। f + g, f - g and $\dfrac{f}{g}$ और ज्ञात कीजिए

Answer 1

Answer:

step-by-step explanation:

Given that,

f(x) = x + 1

g(x) = 2x - 3

Now,

f(x) + g(x)

= x + 1 + 2x -3

= 3x - 2

Also,

f(x) - g(x)

=( x + 1 ) - ( 2x - 3 )

= x - 2x + 1 + 3

= 4 - x

Again,

$\frac{f(x)}{g(x)}$

= $\frac{x+1}{2x-3}$

Answer 2

$\huge\bold\pink{hey friend}$

$<b>Solution$

⬇⬇⬇

The questions states the following:-

$f(x) = (x + 1)$

$g(x) = (2x - 3)$

f( x ) + g( x )

Substitute for x in each cases. In the first case x = ( x + 1 ) while in the second case x = ( 2x - 3 ).

[ f ( x + 1 ) ] + [ g ( 2x - 3 ) ]

$\therefore{x + 1 + 2x - 3}$

$\therefore{3x - 2}$

Next,

f ( x ) - g ( x )

Again substitute for x in each cases. In the first case x = ( x + 1 ) while in the second case x = ( 2x - 3 ).

[ f ( x + 1 ) ] - [ g ( 2x - 3 ) ]

$\therefore{x - 2x + 1 + 3}$

$\therefore{4 - x}$

Next,

$\frac{f(x)}{g(x)}$

Again substitute for x in each cases. In the first case x = ( x + 1 ) while in the second case x = ( 2x - 3 ).

$\frac{x + 1}{2x + 3}$

▶@princessemaanu2006◀

$<marquee>thanks for asking$
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