माना , , निम्न का मान निकालिए l (i) , (ii)
Answers
Step-by-step explanation:
this is soo weird i never seen such complicated stuff before
(i) (z₁z₂/z₁bar) = (2-i)(-2+i)/(2-i)bar
= -(2-i)(2-i)/2+i
= -(2-i)²/2+i
= -(4+i²-4i)/2+i
= -(4-1-4i)/2+i
= -(3-4i)/2+i
= -(3-4i)/(2+i) ₓ (2-i)/(2-i)
= (-6-4i²+3i+8i)/(4-i²)
= -6+4+11i/5
= -2+11i/5
= -2/5 + 11i/5
इसलिए Re(z₁z₂/z₁bar) = -2/5
(ii) 1/z₁.z₁bar = 1/(2-i).(2-i)bar
= 1/(2-i)(2+i)
= 1/4-i²
= 1/5
इसलिए Im(1/z₁.z₁bar) = 0
More Question:
प्रश्न 1 से 2 तक सम्मिश्र संख्याओं मे प्रत्येक मापांक और कोणाक ज्ञात कीजिए : z = - \sqrt 3 + \iota
https://brainly.in/question/8941760