Question

Magnetic field intensity at the center of a coil of 50 turns, radius 0.5 m and carrying a current of 2 a is

Answer 1

using the formula,

$B=\frac{\mu_0Ni}{2r}$

where $\mu_0$ is permeability of the space/vaccum.i.e., $\mu_0$ = 4π × 10^-7 Tm/A

N is number of turns , i current through coil and r is the radius of the coil.

here , N = 50, i = 0.5m and I = 2A

so, B = (4π × 10^-7 × 50 × 2)/(2 × 0.5)

= 4π × 10^-7 × 100 T

= 4π × 10^-5 T

we know, π ≈ 3.14

so, B = 4 × 3.14 × 10^-5 T = 12.56 × 10^-5 T = 1.256 × 10^-4 T