Make a diagram to show how hypermetropia is corrected. The near point of a hypermetropic eye is 1m.What is the power of lens required to correct this defect? Assume that the near point of the normal eye is25 cm.
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Explanation:
For hypermetropic eye can see the nearby object kept at 25 cm (at near point if normal eye) clearly if the image of this object is formed at its own near point which is 1 meter here. thus , power of convex lens required is +0.33D . Brainly Answering Legend Contest is active.
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