Question

Man pulling a bag of sugar with a means of rope inclined at angle 60 Degree to the Horizontal. If the tension in the rope is 100N, find the effective force pulling the bag

Answer 1

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Explanation:

Tension in the rope T

T=Mg

N normal reaction between man and ground

N=60g−Tsin60

f=μN=Tcos60

N=600−10M

2

3

f=

2

1

[600−10M

2

3

]=M×10×

2

1

600−5

3

M=10M

600=5

3

M+10M

M(5

3

+10)=600

M=

(5

3

+10)

600

M=32.15kg

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