Manav has small box with ₹ 740 in coins of denominations ₹ 1,₹2 and ₹5 . If the number of coin of denomination of ₹ 2 are 3 times a the number of coins of denomination of ₹1 and the number of coins of denomination of ₹5 are twice the number of coins of ₹2 how many coins of each denomination does manav has ?
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Let us assume x,y,z be no of coins of 1 , 2 and 5 respectively
y = 3x and z = 2y
Value = x+2y+5z = 740 becomes x+2(3x)+5(2)(3x) = 740
37x = 740
x = 20: y = 60 and z = 120
There are 20 coins of 1 re, 60 coins of Rs. 2 and 120 coins of Rs. 5/-
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