Math, asked by navneetprajapati2345, 8 months ago

Maninder bought two horses at Rs.40,000 each. He sold one horse at 15% gain, but

had to sell the second horse at loss. If he had suffered a loss of Rs.3,600 on the

whole transaction, then the selling price of the second horse is​

Answers

Answered by Anonymous
13

Answer:

Rs. 30400

Step-by-step explanation:

Purchase cost of two horses = 2 × 40000 = Rs. 80000

Selling cost of two horses = 80000 - 3600 = Rs. 76400

Sell cost of 1st horse at 15% profit = 40000 + 15% of 40000 = Rs. 46000

∴ Sell cost of 2nd horse = 76400 - 46000 = Rs. 30400

Answered by Anonymous
21

 \large\bf\underline{Given:-}

★ Cost price of each horse = Rs 40,000

★ he sold 1st horse at a gain of 15%

★ he had a loss of Rs 3600 on whole transaction.

 \large\bf\underline {To \: find:-}

  • selling price of Second horse.

 \huge\bf\underline{Solution:-}

Cost price of both horses = (40000×2)

Cost price of both horses = Rs 80000

Selling price of both horses = C.P - loss

Selling price of both horses = 80000 - 3600

Selling price of both horses = 76400

We know that,

When we have a gain then,

\large\bf \: S.P = \frac{(100  +  profit\%)}{100}  \times C.P \:

Spelling price of 1st horse = (100+15)/100×40000

Spelling price of 1st horse = 115 × 400

Spelling price of 1st horse = Rs 46000

Now,

➝ S.P of 2nd horse = S.P of both horses - S.P of 1st horse.

➝ S.P of 2nd horse = 76400 - 46000

S.P of 2nd horse = Rs 30400

So,

Selling price of Second horse = Rs30400

Here,

  • S.P = Selling price
  • C.P = Cost price
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