Manisha has a kitchen garden in the shape of a rhombus. The perimeter of yhe garden is 40 m and its diagonal is 16 m. She wants to divide it into two equal parts and use these parts in rotation. Find the area of each part of the garden.
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Solution :-
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Perimeter of the garden=40m
Length of each side of the rhombus=(40/4)m=10m
let length of the 2nd diagonal be x m
∴ a=÷2 (a:length of side, m:length of first diagonal, n:length of second diagonal)
=>2×10=
=>(20)²=256+n²
=>400=256+n²
=>n²=400-256=144
=>n=12m
Length of second diagonal=12m
Area of the garden=(m×n)÷2
=(16×12)÷2
=96m²
Area of each part of garden=(96÷2)=48m²
✌️ I THINK IT HELPED YOU ✌️
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Solution :-
=============
Perimeter of the garden=40m
Length of each side of the rhombus=(40/4)m=10m
let length of the 2nd diagonal be x m
∴ a=÷2 (a:length of side, m:length of first diagonal, n:length of second diagonal)
=>2×10=
=>(20)²=256+n²
=>400=256+n²
=>n²=400-256=144
=>n=12m
Length of second diagonal=12m
Area of the garden=(m×n)÷2
=(16×12)÷2
=96m²
Area of each part of garden=(96÷2)=48m²
✌️ I THINK IT HELPED YOU ✌️
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