Question

manufacturer test 7000 LED lights at random and found them 25 of them were defective .if a LED light is selected at random what is the probability?

Answer 1

NO. OF TOTAL OUTCOMES=7000
No. of non defective bulbs=7000-25= 6975
so, the P(of getting a non defective bulb)=6975/7000= 279/280

Also the P(of getting a defective bulb)= 25/7000= 1/280

Answer 2

Question:

A manufacturer tested 7000 led lights at random and found and found that 25 of them were defective if a a led light is selected at random what is is the probability that the selected led light is a defective one

Answer:

Probability that the selected led light is a defective one is 1/280

Solution:

Given that,

Manufacturer test 7000 LED lights at random and found them 25 of them were defective

Total number of possible outcomes = 7000

Defective ones = 25

The probability of an event is given as:

$Probability = \frac{ \text{ number of favorable outcomes }}{ \text{ total number of possible outcomes }}$

Therefore, probability that the selected led light is a defective one is:

$Probability = \frac{25}{7000} = \frac{ 1}{280}$

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