Question

marbel rolling on a smooth floor has an initial velocity of 0.4m/s . if floor offers a retardation of o.o5 m/s . calculate time it will take to come to rest​

Answer 1

Time required by body to come in rest is 8seconds. As we know 1st equation of motion v= u+ at , here v is final velocity equal to zero and as the body deaccelerates so a is in negative so , 0 = 0.4 - 0.05t

t = 0.4/0.05 = 8s