Question

marry,david and joseph done a work in 10,12,15 days. they all satrt together.after 3 days david left the work. then how many days mary and jospeh together complete this remaining work?​

Answer 1

Answer:

In 1 day M, D and J work 1/10, 1/12 and 1/15

So in 3 days together they will finish

3×{(1/10) + (1/12) + (1/15)} work = 3/4 work

Remaining work to be finished = 1 - (3/4) = 1/4

In 1 day M and J can finish (1/10) + (1/15) = 1/6 work

So 1/6 work is done in 1 day

So remaining 1/4 work can be finished in 6×(1/4) =3/2 = 1.5 days = one and half days