Question

. Mass and volume of a block are measured as
22.42 g and 4.7 cm. The maximum possible error
in density is
(1) 0.6%
(2) 2.2%
(3) 2.8%
(4) 3.2%​

Answer 1

Answer:

The maximum possible error in density is 2.2 %.

(2) is correct option.

Explanation:

Given that,

Mass = 22.42 g

Volume = 4.7 cm³

Suppose the maximum possible error of mass and volume are 0.01 g and 0.1 cm³.

The density is equal to the mass of block divided by the volume of block.

We need to calculate the maximum possible error in density

Using formula of density

$\dfrac{\Delta\rho}{\rho}\times100=\dfrac{\Delta m}{m}\times100+\dfrac{\Delta V}{V}\times100$

Put the value into the formula

$\dfrac{\Delta \rho}{\rho}\times100=\dfrac{0.01}{22.42}\times100+\dfrac{0.1}{4.7}\times100$

$\dfrac{\Delta\rho}{\rho}\times100=2.2\%$

Hence, The maximum possible error in density is 2.2 %.

Answer 2

Answer:

2.2 %

Explanation: