Question

Mass of 2kg is attached to a spring of force constant 200N/m. Find its time period?

Answer 1

Answer:

0.63 Seconds

Explanation:

Given the mass of an object and the spring constant the period T is given by :

T = 2 pie × square root of (m/k)

Whereby :

T = the period.

m = mass of the object

k = Spring constant

In this case we have been given the following :

m = 2kg

k = 200N/m

Pie = 22/7

Doing the substitution we have :

T = 2 × 22/7 × square root (2/200)

T = 44/7 × 0.1 = 0.628 S

The period is 0.63 seconds