Question

transverse wave propagates in a medium with a velocity of 1450 m per second the distance between the nearest points at which the oscillations of the particle carried in the opposite Phase pi is 0.1 M what is the frequency of the wave

Answer 1

Answer:

Explanation:

It is given that,

=> Velocity of Transverse wave v = 1450 metre / second  

=> Path difference = 0.1 M

=> Frequency of the wave = ?

=> difference of phase = 2π/⋋ * difference of path

π = 2π/⋋ * 0.1

⋋ = 2π/ π * 0.1

⋋ = 2 * 0.1

⋋ = 0.2m

=> now, Velocity of Transverse wave:

v = n⋋  

∴ n =  v / ⋋  

= 1450 / 0.2

= 7250 Hz

Therefore, the frequency of the wave is 7250 Hz.