Question

Mass of glucose C6H12O6

produced by mixing

9 moles of carbon, 24 g. of hydrogen and

67.2L O2

at STP according to given reaction, is

(s) 2(g) 2(g) 6 12 6(s) 6C 6H 3O C H O + + →

1) 90 g
2) 180 g

3) 240 g
4) 360 g​

Answer 1

The mass of glucose produced is 180 gram

Therefore, option (2) is correct.

Explanation:

Given:

9 moles of Carbon, 24 grams of Hydrogen and 67.2 L of Oxygen are mixed to produce Glucose (C₆H₁₂O₆)

To find out:

The mass of Glucose

Solution:

The balanced reacting to produce glucose is

6C + 6H₂ + 3O₂ → C₆H₁₂O₆

Moles of Carbon = 9 (given)

Moles of Hydrogen present = 24/2 = 12

Moles of Oxygen present = 67.2/22.4 = 3

Here Oxygen is the limiting reagent i.e. it will be consumed fully

According to the reaction above

3 moles of Oxygen gives 1 moles of glucose

Therefore, mass of glucose = 1 × molecular weight of glucose = 1 × 180 = 180 gram

Hope this answer is helpful.

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