Question

mass of nacl required to prepare 0.01 m aqueous solution in 1 kg water is

Answer 1

Molality (m) = Moles of solute / Mass of solution in kg
0.01 = n / 1
n = 0.01 moles

0.01 mole of NaCl is required.

Mass of 0.01 mole of NaCl
M = 0.01 × 58.44 g/mol
M = 0.584 g

Mass of NaCl required is 0.584 g

Answer 2

Given:

Element = Nacl

To Find:

Mass of Nacl required to prepare 0.01 m aqueous solution in 1 kg water

Solution:

Molality = Moles of solute / Mass of Solvent

Moles of solute = 1 mol

0.01 = n / 1

n = 0.01 moles

Now,

0.01 mole of NaCl is required.

Therefore,

Mass of 0.01 mole of NaCl

= 0.01 × 58.5

= 0.585

Answer: The mass of NaCl required is 0.585 gm

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