Maths
Find the HCF of 32,64,96,160.
Plz give the answer step by step.
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Answer:
Prime factorisation method :
1 ) 32 = 2^5
2 ) 64 = 2^6
3 ) 96 = 2^5 × 3
4 ) 128 = 2^7
Therefore,
HCF ( 32 , 64 , 96 , 128 ) = 2^5
= 32
I hope this helps you.
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Answered by
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my method is a bit odd
Step-by-step explanation:
first we will find all the factors of the following numbers
32= 1,2,4,8,16,32
64 = 1,2,4,8,16,32,64
96 = 1,2,3,4,6,8,12,16,24,32,48,96
160 = 1,2,4,5,8,10,16,20,32,40,80,160
now we will take out the common factors in the number
that is - 1,2,4,8,16,32 now we will see which is the greatest factor i.e 32 is the answer
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