Math, asked by VaibhaviPaliwal, 7 days ago

Maths

Find the HCF of 32,64,96,160.

Plz give the answer step by step.​

Answers

Answered by chanshi27
0

Answer:

Prime factorisation method :

1 ) 32 = 2^5

2 ) 64 = 2^6

3 ) 96 = 2^5 × 3

4 ) 128 = 2^7

Therefore,

HCF ( 32 , 64 , 96 , 128 ) = 2^5

= 32

I hope this helps you.

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Answered by DrStonefan
0

my method is a bit odd

Step-by-step explanation:

first we will find all the factors of the following numbers

32= 1,2,4,8,16,32

64 = 1,2,4,8,16,32,64

96 = 1,2,3,4,6,8,12,16,24,32,48,96

160 = 1,2,4,5,8,10,16,20,32,40,80,160

now we will take out the common factors in the number

that is - 1,2,4,8,16,32 now we will see which is the greatest factor i.e 32 is the answer

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