Question

Maths question answer fast.

Answer 1

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Answer 2

Answer:

Hello.

I hope this helps.  Have a great day!!!

Hmmm.  I believe there's a mistake in the question.  This is suggested by the sum of x² and A² that have different units.

It should be x⁴ + 4A² under the square root sign.

Proceeding then....

Since area of triangle = (1/2) × base × height, the other leg of the right angled triangle is 2A / x.

By Pythagoras' Theorem, the hypotenuse is then

√( x² + (2A/x)² ) = √( ( x⁴ + 4A² ) / x² ) = √( x⁴ + 4A² ) / x

Look at the triangle with the hypotenuse as "base".  The length that we want is then the height.  Again using area = (1/2) × base × height, we get

height = 2A / base

= 2A / hypotenuse

= 2Ax / √( x⁴ + 4A² )