Question

max is as twice as old an jane. five years ago his age was three times more of Jane's age. find their percentage ages
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Answer 1

Answer:

let

Step-by-step explanation:

let Jane's age be x

and max=2x

five years ago,

Jane's age =x-5

Max's age = 2x-5

therefore, ATQ

3(x-5)=2x-5

3x-15= 2x-5

3x-2x=-5+15

x=10 years

so

Jane's age=10 years

and Max's age=2×10= 20 years

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