mean of four abservations is 12. if first,second,third and fourth abservations are decreased by 1,2,3,and 4 respectively, then find the new mean
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let the original mean be x
x/4 = 12
x= 48
1+2+3+4=10
New mean = (48-10)/4
= 9.5
x/4 = 12
x= 48
1+2+3+4=10
New mean = (48-10)/4
= 9.5
Ashishprakash1:
brilliant ro
Gd
why u take 1+2+3+4 when it is decreased in question
plz explain me
x - 1-2-3-4-5 = x-(1+2+3+4)
ohhh
a new question
find the 17th ferm from the last of the AP 1,6,11,16,.........201,216.
answere my question
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