measure of one side of a right triangular field is 4.2m. if the difference of the length of the hypotenuse and the other is 14m. find the sides and area of the triangle
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Let the perpedicular, p=4.2 m and base is b m, hypotenuse is h m.
Then by the given question, h-b=14⇒h=b+14
Then by Pythagoros's theorem,
p²+b²=h²
or, (4.2)²+b²=(b+14)²
or, 17.64+b²=b²+2.b.14+196
or, 17.64=28b+196
or, 28b=-178.36
or, b=-178.36/28
or, b=-6.37
Since any side of a triangle can't be negative that means the datas given are wrong
Read more on Brainly.in - https://brainly.in/question/613412#readmore
Then by the given question, h-b=14⇒h=b+14
Then by Pythagoros's theorem,
p²+b²=h²
or, (4.2)²+b²=(b+14)²
or, 17.64+b²=b²+2.b.14+196
or, 17.64=28b+196
or, 28b=-178.36
or, b=-178.36/28
or, b=-6.37
Since any side of a triangle can't be negative that means the datas given are wrong
Read more on Brainly.in - https://brainly.in/question/613412#readmore
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