Question

MECH Technical
Apitude
Q No.: 7
According to parallel axis theorem, the moment of inertia of a section about an axis parallel to
the axis through centre of gravity (i.e. IP) is given by(where, A = Area of the section, IG =
Moment of inertia of the section about an axis passing through its C.G., and h = Distance
between C.G. and the parallel axis.)
O(A). IP = 1G + Ah2
(B) [P = G - Ah2
(C). IP = Ah2 / IG
(D). IP = Ah2 / IG​

Answer 1

Answer:

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