Question

Mechanism of a hypothetical reaction X2 + Y2 ----> 2XY is given below:

X2 ---> X + X (fast)
X + Y2 ----> XY + Y (slow)
X + Y ------> XY (fast)

The overall order of the reaction will be?​

Answer 1

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Answer 2

QUESTION ===》》》

Mechanism of a hypothetical reaction X2 + Y2 ----> 2XY is given below:

X2 ---> X + X (fast)

X + Y2 ----> XY + Y (slow)

X + Y ------> XY (fast)

The overall order of the reaction will be?

ANSWER =====》 》

1.5

SOLUTION ===》》》

The Rate Law is the expression in which reaction rate is given in terms of molar concentration of reactants with each term raised to some power, which may/maynot be equal to stoichiometric of the reacting species in a balanced chemical equation

a A + bB ----》》 cC + dD

$rate \: = \frac{dr}{dt}$

$\alpha |a {}^{x} | . |b {}^{x} |$

$k |a {}^{x} | . |b {}^{x} |$

k = Constant

X2 ==》》 X + X (fast)

X + Y2 ===》》 XY + Y (slow)

Rate = k [x][y2]

k = [x]^2 /[x2]

$|x| = \sqrt[]{k(x2)} \\ \\ k. \sqrt[]{(x2).(y2)} \\ \\ k1. \sqrt{(x2) {}^{ \frac{1}{2} } .(y2)} \\ \\ 1 + \frac{1}{2} \\ \\ \frac{3}{2} \\ \\ \huge \bold{answer \: = 1.5}$