Question

Medians of triangle abc intersect at g if area of triangle abc is equal to 27 cm square the area of bgc is equal to

Answer 1

3cm square......For explanation ask again

Answer 2

Area of ΔBGC =   9 cm²

Step-by-step explanation:

Let say AD , BE & CF are median intersecting at G

three medians together divide a triangle into six equal parts

Area of ΔAGE =  ΔCGE  = ΔCGD = ΔBGD = ΔBGF =  ΔAGF

Area of  ΔAGE +  ΔCGE  + ΔCGD + ΔBGD + ΔBGF +  ΔAGF = Area of ΔABC

=>Area of ΔAGE =  ΔCGE  = ΔCGD = ΔBGD = ΔBGF =  ΔAGF = 27/6  cm²

Area of Area of ΔBGC = Area of ΔBGD + ΔCGD

=> Area of Area of ΔBGC =  27/6 + 27/6

= 54/6

= 9 cm²

Area of ΔBGC =   9 cm²

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