Question

Meena is 6 years older than her brother Ajay if the sum of their ages is 28 years what are their present ages

Answer 1

let, Ajay 's present age be x
Meena 's present age be x + 6
A/Q. x + x + 6 = 28
2x = 28- 6
x = 22/2
x = 11
therefore,present age of Ajay =11years
present age of Meena = 17Years ans

Answer 2

let the age of Ajay=x
then let the age of meena=x+6
given that the sum of they ages=28
therefore, x+x+6= 28
x+x+6=28
2x=28-6
2x=22
x=22÷2
x=11
verification=
11+6+11
=28
therefore 28=28
LHS=RHS