Meena went to a bank to withdraw Rs.2000. She asked the cashier to give Rs. 50 and Rs. 100 notes only . Meena got 25 notes in all . Find how many notes of Rs.50 and Rs.100 she received.
Answers
Answered by
1537
Let no. of Rs. 50 notes = x
no. of Rs. 100 notes = y
Total notes = 25
⇒ x + y = 25
⇒ x = 25-y
total amount only in Rs. 50 notes = 50x
total amount only in Rs. 100 notes = 100y
Total amount = 2000
⇒ 50x + 100y = 2000
⇒50(25-y) + 100y = 2000
⇒50×25 - 50y + 100y = 2000
⇒1250 +50 y = 2000
⇒ 50y = 2000-1250 = 750
⇒ y = 750/50 = 15
x = 25-15 = 10
No. of Rs. 50 notes = 10
No. of Rs. 100 notes = 15
no. of Rs. 100 notes = y
Total notes = 25
⇒ x + y = 25
⇒ x = 25-y
total amount only in Rs. 50 notes = 50x
total amount only in Rs. 100 notes = 100y
Total amount = 2000
⇒ 50x + 100y = 2000
⇒50(25-y) + 100y = 2000
⇒50×25 - 50y + 100y = 2000
⇒1250 +50 y = 2000
⇒ 50y = 2000-1250 = 750
⇒ y = 750/50 = 15
x = 25-15 = 10
No. of Rs. 50 notes = 10
No. of Rs. 100 notes = 15
magzzzz:
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Answered by
411
Answer:
Step-by-step explanation:
Given :-
Meena went to a bank to withdraw Rs.2000.
She asked the cashier to give Rs. 50 and Rs. 100 notes only .
Meena got 25 notes in all .
Solution :-
Let the number of Rs 50 notes and Rs 100 notes be x and y.
According to the question,
⇒ x + y = 25 ... (i)
⇒ 50x + 100y = 2000 ... (ii)
Multiplying equation (i) by 50, we get
⇒ 50x + 50y = 1250 ... (iii)
Subtracting equation (iii) from equation (ii), we get
⇒ 50y = 750
⇒ y = 15
Putting this value in equation (i), we have
⇒ x = 10
Hence, Meena has 10 notes of Rs 50 and 15 notes of Rs 100.
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