Mehul’s age is 3 more than 5 times the age of Mihir. Three years later mehul’s age will be four times that of Mihir find their present ages.
Answers
Answer:
Present age of Mihir is 6 year and Mehul is 33 year.
Step-by-step explanation:
Let :
Present age of Mihir is a year
Then, present of Mehul should be ( 3 + 5 times of a ) year
Present age of Mehul is ( 5a + 3 ) year
Three year later :
= > Mihir's age = present age + 3 year
= a year + 3 year
= > Mehul's age = present age + 3 year
= ( 5a + 3 ) year + 3 year
According to the question : three years later Mehul’s age will be four times that of Mihir.
= > ( 5a + 3 + 3 ) year = 4( a + 3 ) year
= > 5a + 6 = 4a + 12
= > 5a - 4a = 12 - 6
= > a = 6
= > a year = 6 year
Hence, present age of Mihir is 6 year and Mehul is 33 year { i.e. 5( 6 ) + 3 = 30 + 3 }
Mihir's present age = 6 years
Mehul's present age = 33 years
Let Mihir's present age = x years
•°• Mehul's present age = (5x + 3) years
Three years later,
Mihir's age = (x + 3) years
Mehul's age = (5x + 3 + 3) = (5x + 6) years
According to the question,
5x + 6 = 4(x + 3)
=> 5x + 6 = 4x + 12
=> 5x - 4x = -6 + 12
=> x = 6
Hence,
Mihir's present age = x = 6 years
Mehul's present age = 5x + 3 = 5(6) + 3 = 33 years