metal pipe is 77 cm long the inner diameter of the cross is section is 4 cm and thickness of metal is 0.2cm then outer surface area is
Answers
Answer:
968 cm
Step-by-step explanation:
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A metal pipe is 77 cm long. The inner diameter of a cross section is 4 cm, the outer diameter being 4.4 cm (see Fig. 13.11). Find its
(i) inner curved surface area,
(ii) outer curved surface area,
(iii) total surface area.
GIVEN :-
Length = 77 Cm.
Inner Diameter = 4 Cm.
Thickness = 0.2 Cm.
TO FIND :-
(i) inner curved surface area,
(ii) outer curved surface area,
(iii) total surface area.
SOLUTION :-
(i) inner curved surface area
According to the question inner diameter is 4 cm,
then,
Inner radius of a cylindrical pipe = r1
= Innner diameter/2
= (4/2)cm
= 2cm
Height (h) of cylindrical pipe = 77 cm,
Curved Surface Area of inner surface of pipe =2πr1h
= (2×22/7×2.2×77)cm²
= 968cm²
(ii) Outer curved surface area
According to the question outer diameter is 4.4 cm
Outer radius of cylindrical pipe = r2
= Outer diamter/2=(4.4/2)cm=2.2cm
Height of cylinder
=> h = 77 cm,
Curved area of outer surface of pipe
= 2πr2h
= (2×22/7×2.2×77)cm²
= (2×22×2.2×11)cm2
= 1064.8cm²
(iii) Total surface area
Total surface area = curved surface area of inner cylinder + curved surface of outer cylinder + 2 × Area of base.
Area of base = area of circle with radius 2.2 cm - Area of circle with radius 2 cm
= πr2²−πr1²
= 7
= 22/7×((2.2)²−(2)²)
= 22/7×(4.84−4)
= 22/7×(0.84)
= 2.74cm²
Total surface area = curved surface area of inner cylinder + curved surface area of outer cylinder + 2 × Area of base.
= 968+1064.8+2×2.74
= 2032.8 + 5.76
= 2039.08cm²
Therefore, the total surface area of the cylindrical pipe is
= 2039.08cm²