Question

middle term split of
${x }^{2} + 32x - 420$
​

Answer 1

Answer:

${x}^{2} + 32x + - 420$

${x}^{2} - 42x + 10x - 420$

$x(x - 42) + 10(x - 42)$

$x - 42 = 0 \: \: \: \: \: \: \: \: \: \: \: \: \: x + 10 = 0$

$x = 42 \: \: \: \: \: \: \: \: \: \: \: \: x = - 10$

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