Math, asked by Subhashjambhulkar358, 1 year ago

Milk in a container which is in the form of frustum of a cone of height 30 cm and ready of whose lower and upper circular and are 20 cm and 40 cm respectively is to be distributed in a camp for flood victims if the milk is available at the rate of Rs 35 per litre and 880 l of milk is really needed for a camp find how many such container milk are needed for a camp and what cost will it put on the donor agency for this

Answers

Answered by ankita6853
13
.......
may this help u.........
Attachments:

vismayaaryan: Cost of 1l milk is ₹35 not ₹30
ankita6853: sorry actually in my book it was that so....
Answered by Vamprixussa
5

Hello mate,

Here is your answer,

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Given--Radius of lower end (R1) = 20cm

           Radius of upper end (R2)= 40 cm

           Height (H)= 30 cm

So the volume of container= 1/3 pi H ( R1² + R2² + R1R2)

                                         = 1/3 * 22/7 * 30 ( (20)² + (40)² + 40* 20)

                                         = 1/3 * 22/7 * 30 ( 400 + 1600 + 800)

                                         = 1/3* 22/7 * 30 * 2800

                                         = 88000 cm³ or 88 litres.

Amount of milk required = 880 litre

No. of containers needed will be= 880/88= 10 containers

Cost of 1 litre milk= Rs. 30

So, Cost of 880 litre= 880 * 30 = Rs. 26400

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HOPE THIS HELPS YOUU :)

AND STAY BLESSED.

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