missing in the following series
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Hey mate.... Here is your answer:
86)
Given the data,
Every odd term (3 onwards) is the previous term (say a), a*3–3.
And ,
Every even term is the previous term (say b), b*2–2.
6*2-2=10 (2nd term)
10*3-3=27 (3rd term)
27*2-2=52 (4th term)
52*3-3=153 (5th term)
153*2-2=304 (6th term)
304*3–3=909 (7th term)
#Be Brainly✌️
86)
Given the data,
Every odd term (3 onwards) is the previous term (say a), a*3–3.
And ,
Every even term is the previous term (say b), b*2–2.
6*2-2=10 (2nd term)
10*3-3=27 (3rd term)
27*2-2=52 (4th term)
52*3-3=153 (5th term)
153*2-2=304 (6th term)
304*3–3=909 (7th term)
#Be Brainly✌️
charan3519:
thankyou
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