Question

mmmmm......mela question....



plzzz sove 7 and 8 urgent....

Answer 1

Q7

PQR is a triangle in which DE || QR. Line DE intersects PQ at D so that PD = DQ

To Prove: PE = ER

In Δ PQR and Δ PDE;

(Because as per BPT, these are similar triangles.)

Hence; E is the midpoint of PR proved.

Q8

The figure from the previous question can be used to solve this question.

ABC is a triangle in which D and E are mid points of PQ and PR respectively.

To Prove: DE || QR

In Δ PQR and Δ PDE;

Hence, as per BPT these triangles are similar.

Hence; DE || QR proved.