mno2+4hcl=mncl2+cl2+h2o
the valency factor of hcl is?
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7
Answer:
1.
Explanation:
MnO2+4HCl -> MnCl2+Cl2 + H2O from this reaction we get that the Mn02 is reduced to the MnCl2. So by calculating we get that the oxidation number of the Mn decreases from +4 state to the -2 state.
The HCl is oxidised to the chlorine molecule and the oxidation number increases from -1 to 0. So, the n-factor of the HCl will be 1 irrespective of 4 mol of HCl is required to form 1 mol or MnCl2.
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