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☆ Sequence in rolling of dice
If you roll a 10-sided dice 3 times, what is the probability that they form neither a strictly increasing nor a strictly decreasing series?
Answers
Answer:
Step-by-step explanation:0.64. That was too easy kid.
0.76
Step-by-step explanation:
Given that,
A 10-sided dice is rolled thrice
To find,
The probability that they form neither a strictly increasing nor a strictly decreasing series = ?
Procedure:
Assume the strictly increasing series = x
Assume the strictly decreasing series = y
& Assume the number of neither strictly decreasing nor strictly increasing series be = z
Therefore,
x + y + z = 1000 (Total possible outcomes = 10 * 10 * 10 = 1000)
A series that is strictly increasing from the opposite side would appear to be a strictly decreasing series. Therefore,
x = y
Hence,
2x + z = 1000
In the case of a strictly increasing series, all the 3 numbers would be distinct. So, possible ways = 10C3.
Therefore,
z = 1000 - (10C3) × 2
∵ z = 760
∵ Probability(p) of getting neither a strictly increasing nor a strictly decreasing series = favorable outcomes/Total outcomes
= 760/1000
= 0.76
Learn more: Find the probability
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