Question

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The shape of the top surface of a table is a trapezium. Find its area if its parallel sides are 1 m and 1.2 m and perpendicular distance between them is 0.8 m.

Answer 1

Area of trapezium= 2/1× sum of parallel sides× perpendicular distance

Parallel sides= 1 and 1.2m

Perpendicular distance=0.8m

So,

Area= 2/ 1×(1+1.2)×0.8

=1.1×0.8

=0.88m²

Answer 2

Answer:

▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬

$\underline{\green {\sf Given:- }}$

First parallel side = 1 m

Second parallel side = 1.2 m

Perpendicular distance between them = 0.8 m

$\underline{\pink {\sf To\:Find:- }}$

Area of the trapezium = ?

$\underline{\orange {\sf Solution:- }}$

We know that,

$\large\boxed{\underline{\purple{\sf Area\:of\:the\:trapezium = \dfrac{1}{2} \times (a+b)\times h }}}$

Here,

→ a = 1.2 m

→ b = 1 m

$⇢ \:\: \sf{\dfrac{1}{2} \times (1.2 + 1) \times 0.8}$

$⇢ \:\: \sf{\dfrac{1}{2} \times 2.2 \times 0.8}$

$⇢\:\:\underline{\boxed{\pink{\mathfrak{0.88\:m^2}}}}$

$\displaystyle\therefore\:\underline{\textsf{The required area is\textbf{ 0.88 m² }}}$