Question

if p(x)=ax2+bx+c and a+c=b then factor of p(x) is​

Answer 1

Answer:

Correct option is

B

atleast two real roots

Given,

P(x)=ax

2

+bx+c

hence for real roots

b

2

−4ac≥0

Q(x)=−ax

2

+dx+c

Hence for real roots,

d

2

+4ac≥0

Now ac



=0

Now if ac<0

then

b

2

−4ac>0

Hence, P(x).Q(x) has atleast two real roots.

If ac>0

then d

2

+4ac>0

Hence P(x).Q(x) has atleast two roots.