Math, asked by rekhaom1984, 9 months ago

mohan is twice as old as sohan. five years ago mohan's age was three time sohan's age. find their present ages
Please give the answer as fast as possible

Answers

Answered by vaghasiyabansari678
2

Step-by-step explanation:

consider, age of Mohan = x and that of Sohan = y

=> x = 2y

=> x - 2y = 0 ----------(i)

Now,

=> x-5 = 3(y- 5)

=> x- 3y = (-15) + 5

=> x-3y= -10 -----------(ii)

solving (i) and (ii)

we get x= 20 and y= 10

=> age of Mohan = 20 years and age of sohan = 10 years

Answered by starley21
0

Answer:

Ans in attachment

Step-by-step explanation:

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