Molar ratio in a mixture of water and absolute alcohol is 0.2. The mole fraction ratio of alcohol and water is?
Answers
The sum of all the mole fractions for the solution = 1
mole fraction of A = 0.2
so mole fraction H2O = 1 - 0.2 = 0.8
molality = moles solute / kg solvent
molar mass H2O = 1.01 * 2 + 16.00 = 18.02 g/mol
mass H2O = 0.8 mol H2O x [18.02 g / mol] x [1 kg / 1000 g] = 0.014 kg H2O
so molality = 0.2 / 0.014 = 14 M(approx
Answer:
5.
Explanation:
as we know that mole ratio of water to alcohol is 0.2
moles of water / moles of alcohol = 0.2/1 = 0.2
we have to find mole fraction of alcohol to water ,
we know the formulae
mole fraction of a A = no of moles of A / no of moles of A + no of moles of B.
mole fraction of alcohol / mole fraction of water = no of moles of alcohol / no of moles of water .
as the bases are same they get cancelled .
= 1/0.2
= 10/2
= 5 .
hope you got this
therefore the final answer is 5 .