prove 1+cosecA 1-sinA=cosA cotA
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(1+1/sinA)(1-sinA)=CosA CotA
=(1+SinA)/SinA (1-SinA)
=(1-Sin(square)A/SinA
=Cos(square)A/SinA
=CotA SinA
hence proved...
=(1+SinA)/SinA (1-SinA)
=(1-Sin(square)A/SinA
=Cos(square)A/SinA
=CotA SinA
hence proved...
Answered by
39
Proved.
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