Question

Mole fraction 1.8g glucose in 90gm water is-
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Answer 1

" Answer:

Molar mass of C6H12O6 = 180 amu

Molar mass of H2O = 18 amu

Number of moles of Glucose = 1.8/180 = 0.01 moles

Number of moles of water = 90/18 = 5 moles

Mole Fraction = Moles of a substance/ Total moles

Mole fraction of glucose = 0.01/(5+0.01) = 0.01/5.01 =  1/501

Mole fraction of Water = 5/(5+0.01) = 5/5.01  = 500/501"