Mole fraction iodine in benzene is 0.2. What is the molarity of iodine in benzene
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Answered by
25
mole fraction = 0.2.
therefore in 100 moles, 20 moles are of solute and 80 moles are of benzene(solvent)
mass of benzene = 80 * Mol.Wt of Benzene = 80* 78 = 6240g
for 6240 g of solvent we have 20 moles of solute
Therefore for 1000g of solvent we have (20)*(1000)/(6240) = 3.20 molal
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therefore in 100 moles, 20 moles are of solute and 80 moles are of benzene(solvent)
mass of benzene = 80 * Mol.Wt of Benzene = 80* 78 = 6240g
for 6240 g of solvent we have 20 moles of solute
Therefore for 1000g of solvent we have (20)*(1000)/(6240) = 3.20 molal
mark as brinliest if possible plz hope you got ur answer
Answered by
11
Let,
the number of moles of Iodine(solute) in benzene(solvent) be 'x' mol.
and,
The mass of solvent(benzene) be '1000g' or '1kg'
Given:
Mole fraction of Iodine = 0.2
To Find:
Molality of iodine in benzene
Solution:
Molar mass of Benzene=78g
Thus, the number of moles of benzene in 1kg of itself is :
A.T.Q:
Now, as
.
Answer:
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